9) One test for vitamin C (ascorbic acid, Call:O%) is based on the reaction of t

Question

9) One test for vitamin C (ascorbic acid, Call:O%) is based on the reaction of the vitamin with iodine: If 25.0 mL of a fruit juice requires 13.0 mL of 0.0100 M I: solution for reaction, what is the molarity of the ascorbic acid in the fruit juice? a) b) The Food and Drug Administration recommends that 60 mg of ascorbic acid be consumed per day. How many milliliters of the fruit juice in part (a) must a person drink to obtain the recommended dosage? 0) In many states, a person with a blood alcohol concentration of 0.080% (v/v) is considered legally drunk. 5.0 L? What volume of total alcohol does this concentration represent, assuming a blood volume of 8.3

Explanation / Answer

a)

mmol of I2 = MV = (13)(0.01) = 0.13

ratio is

1:1 so

0.13 mmol of acid = 0.13 mmol of I2

[Acid] = mmol / V = 0.13 / 25 = 0.0052

b)

m = 60 mg per day

m = 0.06 g

mol = mass/MW = 0.06/192.124 = 0.000312 mol required

M = 0.0052

V = mol/M = 0.000312 /0.0052 = 0.06 liter required = 60 mL required

Q10

Vethanol = 0.08/100* Vtotal

Vethanol = 0.08/100* 5 = 0.004 liter of ethanol in the blood

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