Date: 0O Name: Section: Standardization of NaOH nced Equation for Reaction4pHQ4O

Question

Date: 0O Name: Section: Standardization of NaOH nced Equation for Reaction4pHQ4O4t1Na01-dwandlad. Data Table Trial 1 Trial 2 Trial 3 mass of KHP (g) Moles of added (mol)1841.3-14.1-19.2 FINAL Buret Reading (mL) :8qmLIM4l mL(32.450 INITIAL Buret Reading (mL) 0.20m Volume of NaOH added (mL) :6 q mL | |() : 2 2 mL 14 hk10 lome 114340 1 Volume of NaOH in L Moles of NaOH in sample (mol) Concentration of NaOH (mol/L) Average Conc. NaOH (molVL) %RAD for experiment rvations: Continue on next page if needed Reagent Table Appearance a

Explanation / Answer

mol of NaOH can be found via stoichiometry

mol of KHP = mol of base, since 1:1 ratio

so

mol of NaOH (trial #1 ) = mass of KHP / MW of KHP = 0.236 / 204.22 = 0.00115

mol of NaOH (trial #2 ) = mass of KHP / MW of KHP = 0.318/ 204.22 = 0.00155

mol of NaOH (trial #3 ) = mass of KHP / MW of KHP = 0.437/ 204.22 = 0.00213

For further data:

[NaOH] = mol of NaOH / Volume of NaOH used ( in LITERS!)

[NAOH] average = (sum of all [NaOH] ) /3 trials

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