1. Simple Molarity Problems a. the moles of HF in 275 mL of g. the volume of 11.
ID: 551707 • Letter: 1
Question
1. Simple Molarity Problems a. the moles of HF in 275 mL of g. the volume of 11.7 M KCIO, containing 16.5 g of KCIO 0.65 M HF ans. ans. b. the volume of 1.3 M sulfuric acid h. the moles of solute in 2.83 liters of containing 3.75 moles of sulfuric acid 0.18 M silver nitrate ans. ans. c. the molarity of 135 mL of solution i. the molarity of a solution prepared by containing 0.12 moles of sodium hydroxide dissolving 61.8 g of copper (II) sulfate in 500 mL of water and diluting to 750 mL ans ans. d. the volume of 1.4 M zinc II chloride containing 23.7 g of zinc II chloride j. the volume of 1.2 M potassium hydroxide containing 3.5 moles of potassium hydroxide ans. ans e. the grams of barium hydroxide in k. the grams of solute in 340 mL of 1.5 liters of 0.55 M barium hydroxide 2.5 M sulfuric acid ans. ans. 1. How would you prepare 500. mL of 0.492 M f. the molarity of 184 mL of a solution containing 71.3 g of phosphoric acid potassium sulfate?Explanation / Answer
Molaritty = No. of moles of solute/ volume of solution(L)
a. Molarity= 0.65M
Volume= 275ml
No. of millimoles of HF = 0.65*275=178.75millimoles
moles= 0.1787 moles
b.No of moles of H2SO4= 3.75
Molarity of H2SO4=1.3
Volume of H2SO4=3.75/1.3= 2.884L= 2884mL
c.Volume of NaOH= 135ml
Moles of NaOH=0.12
Concentration of NaOH= 0.12/0.135=0.88M
d. Concentration of ZnCl2= 1.4M
Mass of ZnCl2= 23.7gm
Molecular mass of ZnCl2= 136.3gm
Moles of ZnCl2= 0.174
Volume of ZnCl2= 0.174/1.4=0.124L=124.2mL
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