Use the standard reaction enthalpies given below to determine r H ° for the foll

Question

Use the standard reaction enthalpies given below to determine rH° for the following reaction:

2S(s) + 3O2(g) 2SO3(g)                        rH° = ?

Given:

SO2(g) S(s) + O2(g)                             rH° = +296.8 kJ

2SO2(g) + O2(g) 2SO3(g)                      rH° = -197.8 kJ

Use the standard reaction enthalpies given below to determine rH° for the following reaction:

2S(s) + 3O2(g) 2SO3(g)  rH° = ?

Given:

SO2(g) S(s) + O2(g)  rH° = +296.8 kJ

2SO2(g) + O2(g) 2SO3(g)  rH° = -197.8 kJ

Explanation / Answer

lets try to write the given reaction in terms of reactions 1,2,3

required reaction (reaction 1) can be written as

reaction 1 = -2*reaction 1 + reaction 2

so,

delta H = -2*delta H1 + delta H2

= -2*(296.8) + (-197.8)

= -791.4 KJ/mol

Answer: -791.4 KJ/mol

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