Not Set0/100 Print Cakulator-Periodic Table estion 1 of 23 c Sapling Learning A

Question

Not Set0/100 Print Cakulator-Periodic Table estion 1 of 23 c Sapling Learning A newly isolated protein was found to contain 0.733% phenylalanine by weight upon amino acid ana (a) What is the minimum molecular weight for the protein (assuming only one Phe residue per protein molecule)? Number g/mol (b) Gel filtration of the protein gave an estimated molecular weight of 43000 g/mol. How many Phe residues are in the protein? (Enter a whole number). # Phe residues- Hint O Previous Give Up & View Solution e Check Answer 0 Neat about us careers privacy policy terms of use contact us help 8

Explanation / Answer

protein , 0.733 % = 165.2

so that, molarmass of protein = 165.2*100/0.733

              = 22537.51 g/mol

one phe group present in 1 protein.

no of phe residue = 43000/22537.51 = 1.91

answer: 2

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