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can you please show the work the answers are A D B 2) How many grams of Li3N can

ID: 549524 • Letter: C

Question

can you please show the work the answers are A D B

2) How many grams of Li3N can be formed from 1.75 moles of Li? Assume an excess of nitrogen. 2) 6 Li(s) + N2(g) - 2 Li3N(s) A) 20.3 g Li3N B) 61.0 g Li3N C) 58.3 g Li3N D) 15.1 g Li3N E) 18.3 g Li3N 3) In the reaction Cu (s)2Ag (a Cu2* (aq) - 2 Ag (s). the reducing agent (if any) is 3) A) Cu2+ B) Ag* C) Ag. D) Cu. E) none of these (not a redox reaction) 4) Give the net ionic equation for the reaction (if any) that occurs when aqueous solutions of K2S and 4) Fe(NO3)2 are mixed. A) Fe2t(aq)+S2-(aq)+2 Kt(aq) 2 NO3-(aq) Fes(s 2 K*(a) 2 NO3-(aq) B) Fe2t(aq)+S2-(aq) Fes(s) C) K (a)+NO3 (aq) KNO3(s) D) Fe2+(aq)+ S2-(aq)+ 2 Kt(aq) 2 NO3-(aq) Fe2+(aq)+S2-(aq)+2 KNO3(s) E) No reaction occurs.

Explanation / Answer

2)

from given reaction,

when 6 moles of Li reacts, 2 moles of Li3N are formed

o,

moles of Li3N formed = (2/6)*moles of Li

= (2/6)*1.75

= 0.583 moles

Molar mass of Li3N = 3*MM(Li) + 1*MM(N)

= 3*6.968 + 1*14.01

= 34.914 g/mol

we have below equation to be used:

mass of Li3N,

m = number of mol * molar mass

= 0.583 mol * 34.914 g/mol

= 20.3 g

Answer: A

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