Extra credit: Chapter 1. Assignment is worth three points. You must show or expl

Question

Extra credit: Chapter 1. Assignment is worth three points. You must show or explain the process for credit. Due in class November 10. I must understand the writing to give points. 1. Rank the increasing densities of these materials, something that would allow you to decide which one would take up the least space if you needed to transport it from the USA to England: Material A is 4.00 mg/cm3, material B is 5.00 Ib/m3, and material C is 6.00 kg/m Because of the high heat and low humidity in the summer in Death Valley, California, a person might require about a liter of water for every three kilometers traveled on foot Calculate the approximate number of gallons and pounds of water irquired for a person to walk 20 miles in Death Valley 2. 3. If 1.4% of the mass of a human body is calcium, and 2.5.10.1 % is gold, how many grams each of calcium and gold are there in a 205 pound person?

Explanation / Answer

1.

convert all material density in same unit

Density of material A

4.0 mg /cm3

density of material B

5.0 lb/m3

1lb = 453592 mg then 5.0 lb = 2.268 X 106 mg

1.0 m3 = 1000000 cm3

thus density of 5.0 lb / m3 = 2.268 X 106 mg/ 1000000 cm3 = 2.268 mg/cm3

density of material C = 6 kg / m3

1.0 kg = 1000000 mg then 6 kg = 6000000 mg

1.0 m3 = 1000000 cm3

density of 6.0 kg / m3 material = 6000000mg / 1000000cm3 = 6.0 mg/cm3

increasing order of density is Material B < material A < material C

2.

1 mile = 1.60934 kilometer then 20 mile = 20 X 1.60934 = 32.1869 kilometer

person required 1 liter water for 3 kilometer then for to travel 32.1869 kilometer required water =

32.1869 X 1 / 3 = 10.73 liter

person required 10.73 liter water to travel 20 mile

1 liter = 0.264172 gallon then 10.73 liter = 0.264172 X 10.73 = 2.83 gallon

person required 2.83 gallon water to travel 20 mile

1 liter = 2.2 pound water then 10.73 liter = 10.73 X 2.2 = 23.6 pound

person required 23.6 pound water to travel 20 mile

3.

Cacium -

1pound = 453.592 gm then 205 pound = 92986.4 gm

weight of person = 92986.4 gm

calcium present 1.4% that mean 100 gm present 1.4 gm then 92986.4 gm present = 92986.4 X 1.4 / 100 = 1301.8 gm

Calcium present in 205 pound person = 1301.8 gm

Gold -

1pound = 453.592 gm then 205 pound = 92986.4 gm

weight of person = 92986.4 gm

Gold present 2.5 X 10-7% that mean 100 gm present 2.5 X 10-7 gm then 92986.4 gm present =

92986.4 X 2.5 X 10-7/ 100 = 0.000232466 gm

Gold present in 205 pound person = 0.000232466 gm

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