4. A solution of malonic acid, H2C,H204, was standardized by titration with 0.10

Question

4. A solution of malonic acid, H2C,H204, was standardized by titration with 0.1000 M NaOH solution. 20.76 mL of the NaOH solution is required to neutralize completely 12.95 mL of the malonic acid solu- tion, what is the molarity of the malonic acid solution? KHP in 5. Sodium carbonate is a reagen t that may be used to standardize acids in the same way you used a 0.512 g sample of sodium carbonate re- this experiment. In such a standardization, it was found that quired 26.30 mL of a sulfuric acid solution to reach the end point for the reaction. Na2CO3 (aq) + H2SO4 (aq)- H20() + CO2 (g) + Na2SO4 (aq) Copyright © 2015 Pearson Education, Inc

Explanation / Answer

4) 2 mol of NaOH is required to neutralize 1 mol of malonic acid

Molarity of acid = 1/2 (0.1 M * 20.76 mL) / 12.95 mL => 0.08 M

5) 1 mol of Na2CO3 required 1 mol of H2SO4

Molar mass of Na2CO3 = 106 g/mol

0.512 g / 106 g/mol => 0.0048 mol Of Na2CO3

So moles of H2SO4 is also 0.0048 moles

Molality of H2SO4 = 0.0048 mol / 0.0263 L => 0.1836 M

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