gCI2(s) AH =-224 kJ 8. Using the data in Appendix B in Silberberg text or Append
ID: 548170 • Letter: G
Question
gCI2(s) AH =-224 kJ 8. Using the data in Appendix B in Silberberg text or Appendix G in Openstax text, calculate the standard enthalpy change for each of the following reactions: (a) Si(s) + 2F,(g)- SiF,(g) (b) 2C(s) + 2H2(g) + O2(g)- CH3co,H( (c) CH4(g) + N2(g)- HCN(g) + NH3(g) (d) CS,(2) + 3C1,(gCCL4(g) + S,CI (g) 9. In the early days of automobiles, illumination at night was provided by burning acetylene, CH2. Though no longer used as auto headlamps, acetylene is still used as a source of light by some cave explorers. The acetylene is (was) prepared in the lamp by the reaction of water with calcium carbide, CaC2Explanation / Answer
(a)
Si (s) + 2 F2 (g) ---------------> SiF4 (g)
deltaH0r = delaH0f(SiF4) - deltaH0f(Si) - 2 deltaH0f(F2) = - 1615 - 0 - 0 = - 1615 kJ
(b)
2 C (s) + 2 H2 (g) + O2 (g) ------------> CH3COOH (l)
deltaH0r = deltaH0f(CH3COOH) - 2 deltaH0f(C) - 2 deltaH0f(H2) - deltaH0f (O2) = - 487 - 0 - 0 = - 487 kJ
(c)
CH4 (g) + N2 (g) ------------> HCN (g) + NH3 (g)
deltaH0r = deltaH0f (HCN) + deltaH0f(NH3) - deltaH0f(CH4) - deltaH0f(N2)
deltaH0r = 135.1 - 46.19 - ( - 74.85 ) - 0 = 163.8 kJ
(d)
CS2 (g) + 3 Cl2 (g) -----------> CCl4 (g) + S2Cl2 (g)
deltaH0r = deltaH0f(CCl4) + deltaH0f(S2Cl2) - deltaH0f(CS2) - 3 * deltaH0f(Cl2)
deltH0r = - 100.4 - 16.74 - 117 = - 234.1 kJ
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