A. Heat Capacity of a Metal Aluminum Iron Mass of metal piece Volume of water Ma

Question

A. Heat Capacity of a Metal Aluminum Iron Mass of metal piece Volume of water Mass of empty calorimeter cups Mass of calorimeter cups+H2O Mass of water Initial temperature of metal 3.32610.26 30.00 30.00 ml 4.943 4405 g 26.674.33 (temperature of hot H2O bath) Calculations: 30,6 6-69 3.32 1 Iron Temperature Readings, °C Initial 1 minute 2 minutes 3 minutes Aluminum 20,02 2oro 20.03 20.ol 2b.03 o ol 20.02 Add metal to water 4 minutes 21.00 2L0O 2102 5 minutes 6 minutes 7 minutes 8 minutes DO 21.02 2102 2100 Chemistry 131 : EXPERIMENT 7

Explanation / Answer

Alminium

Heat absorbed by H2O will be equal to Heat transferred by metal

Heat transferred by metal = 112.72 J

(m* Cp* delT)water = (m* Cmetal * delT)metal

26.674 g * 4 J/g.C * 1.01 C = 3.326 g * Cmetal * 21.02 C

Cmetal = 1.54 J/g.C

Iron

heat transfered by metal = 81.74 J

(m* Cp* delT)water = (m* Cmetal * delT)metal

19.733 g * 4 J/g.C * 0.99 C = 10.267 g * Cmetal * 21.03 C

Cmetal = 0.362 J/g.C

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