According to the American insurance companies, a driver will travel 12,000 miles
ID: 545833 • Letter: A
Question
According to the American insurance companies, a driver will travel 12,000 miles in a single year. Gasoline may be taken as primarily C8H18, octane, and the reaction with dioxygen is given below. The drivers vehicle gets 30.0 miles per gallon. The density of octane is 0.703g/ml. 2C8H18 + 25O2 - 16CO2 + 18H2O A. How much gasoline in gallons is used in one year? B. How much gasoline in grams is used in one year? C. How much CO2 in grams is produced in a single year? How many pounds of CO2 are produced? According to the American insurance companies, a driver will travel 12,000 miles in a single year. Gasoline may be taken as primarily C8H18, octane, and the reaction with dioxygen is given below. The drivers vehicle gets 30.0 miles per gallon. The density of octane is 0.703g/ml. 2C8H18 + 25O2 - 16CO2 + 18H2O A. How much gasoline in gallons is used in one year? B. How much gasoline in grams is used in one year? C. How much CO2 in grams is produced in a single year? How many pounds of CO2 are produced? 2C8H18 + 25O2 - 16CO2 + 18H2O A. How much gasoline in gallons is used in one year? B. How much gasoline in grams is used in one year? C. How much CO2 in grams is produced in a single year? How many pounds of CO2 are produced?Explanation / Answer
2C8H18 + 25O2 - 16CO2 + 18H2O
A. How much gasoline in gallons is used in one year?
1 gallon = 30 miles
no of gallons = 12000/30 = 400
B. How much gasoline in grams is used in one year?
volume of gasoline in ml = 400*3.785*10^3 (1 gallon = 3.785*10^3 ml)
= 1.514*10^6 ml
mass of octane = v*d
= 1.514*10^6*0.703
= 1.06*10^6 g
C. How much CO2 in grams is produced in a single year? How many pounds of CO2 are produced?
from equation , 2 mol C8H18 = 18 mol CO2
NO of mol of OCtane needed = 1.06*10^6/114.23 = 9279.52 mol
NO of mol of CO2 produced = 9279.52*18 = 1.67*10^5 mol
mass of co2 produced = 1.67*10^5*44
= 7.35*10^6 g
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.