Multiple Choice On the Scantron form, bubble in the letter of the one choice tha

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Multiple Choice On the Scantron form, bubble in the letter of the one choice that best completes the statement or answers the question. No credit will be given for multiple answers 1. Calculate the osmotic pressure of a 0.0120 mol L-1 solution of Na,SO, in water at 10.0"c. Assume that under these circumstances Na SO4 is completely dissociated into ions. A. 0.558 atm B. 0.279 atm C. 0.836 atm D. 0.0930 atm E.0.140 atm 2. Calculate the value of the equilibrium constant K, for the reaction _ NH.cl(s)NH(g) + HCl(g) at 298.15 K based on the following data AGPONH,. g)--16.0 kJ mol- AGP(HCI,g)--95.30 kJ mol-1 A. 0.964 B. 1.04 C. 8.59×10-17 D. 3.16×1019 E. 1.16 x 106 heating according to the reaction 3. Ammonium bydrogen sulfide NHL.HS6) decomposes on NH,HS(s) NH3(g) + H2S(g) At 25 °C the equilibrium enstant of the reaction is Kp 0.11. What is the total pressure at th temperature in a flask that was initially partially filled with a sizeable amount of NH,HS(SY A. 0.44 atm B. 0.012 atm C. 0.11 atm D. 0.66 atm E. 0.33 atm Form B, CHE 132 Exam 2, Fall 2017, Page 1 of 8

Explanation / Answer

P =iCRT
T = 10+273 = 283K
Na2So4 -----------> 2Na^+ (aq) + SO4^2-
   i = 3
P = 3*0.012*0.0821*283
= 0.836atm
C.0.836atm>>>>answer
2. NHCl(s) ----------> NH3(g) + HCl(g)
DG^0 = DG^0f products - DG^0f reactants
      = -95.3-16-(-203) = 91.7KJ/mole   = 91700J/mole
DG^0 = -RTlnKP
91700 = -8.314*298.15*2.303logKp
91700 = -5708.72logKp
logKP = -91700/5708.72
logKp   = -16.063
Kp    = 10^-16.063
        = 8.59*10^-17
C.8.59*10^-17 >>>>answer
3. NH4HS(s) --------> NH3(g) + H2S(g)
     Kp = PNH3*PH2S
     0.11 = x*x
       x^2 = 0.11
        x   = 0.33
total pressure = PNH3 + PH2S
                = 0.33+ 0.33 = 0.66atm

E. 0.66 atm

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