EDTA is a hexaprotic system with the following pK, Values: pkar = 0.00 pK = 1.50
ID: 543695 • Letter: E
Question
EDTA is a hexaprotic system with the following pK, Values: pkar = 0.00 pK = 1.50 pK3 = 2.00 pka = 2.69 pkas = 6.13 pKS = 10.37 - OOCCH CH-COO N-CH-CH2 . OOCCH CH2-COO EDTA (or y) The distribution of protonated forms of EDTA will therefore vary with pH. For equilibrium calculations involving metal complexes with EDTA, it is convenient to calculate the fraction of EDTA that is in the completely unprotonated form, rsee the figure. This fraction is designated any Calculate any at the following two pH values: pH = 3.75 pH 10.85 Number Number a ...Explanation / Answer
Answer
1. At pH =3.75 hydrogen ion concentration =1.8*10-4
One deta have 4 hydrogen so if hydrogen concentration =.0.00018 Than deta concentration ===0.00018/4=0.000045
2..At pH =10.85 hydrogen ion concentration =1.4*10^-11 so
Edta concentration = 1.4*10^-11/40==0.35*10^-11
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