7:48 PM Old Dominion University Pad 91% i Combine and manipulate reactions and c

Question

7:48 PM Old Dominion University Pad 91% i Combine and manipulate reactions and combine and manipulate Hs 43) Calculate the AHR.n for the following reaction: 6 NO2(g) + 8 NH3 (g) 7 N2(g) + 12H20(1) Given Nz (g) + 2 O2(g) 2 NO2(g) Haan = +166.2 kJ 4 NH3 (g) + 3 Oz (g) 2 N2(g) + 6 H2O (l) HRn =-1665.4 kJ a) -1449.1 kJ b) -3330.7kJ c) -3829.4k d) -3497.0k e) -2832.2 kJ 44) Consider the following numbered processes: H for the process A 2C + E is 45) Using Hess's Law, combine the following reactions to create the formation reaction of V203 and calculate the IH" for V2O3-write each reaction and H, in the way they are used to combine and form the formation reaction. 2VCls(s) + 3H20() V2O3(s) + 6HC1(g) 2V(s) + 3Cl2(g) 2VCla(s) 4HCl(g) + O2(g) 2C12(g) + 2H20(1) dH. :-1161.4 kJ 46) Use the first two reactions to determine the enthalpy change of the third reaction N2(g) + O2(g) 2NO (g) HU-180.6 kl 2NO(g) + Cl2(g) 2NOCI (g) H--77.2 kJ 2NOCl (g) N2(g) + O2 (g) + Cla (g) -? a) 84.6 kJ b) 103.4 kJ c) 257.8 k d) -257.8 kJ e) -103.4 kJ

Explanation / Answer

43)

Lets number the reaction as 0,1,2 from top to bottom

Reaction 0 can be written in term of other 2 using:

reaction 0 = -3*reaction 1 + 2*reaction 2

So,

H = -3*H1 + 2*H2

= -3*166.2 +2*(-1665.4)

= -3829.4 KJ

Answer: -3829.4 KJ

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