0 I 36 acpare clta 2. Amounts used - Fill in the information requested for each

Question

0 I 36 acpare clta 2. Amounts used - Fill in the information requested for each reagent used. You need the density of liquids to convert volume (mL) to weight (grams). I.GLI 1.00 11mL mL of acetic acid Density of acetic acid Grams of acetic acid 1.112 Moles of acetic acid ml of sopenty a 0penty alchoIL Density of isopentyl alcohol Grams of isopentyl alcohol Moles of isopentyl alcohol 3. Limiting reagent -According to your calculations above, which reactant is the limiting reagent? @m, a. Acetic acid b. sopentyl alcohol 1.11

Explanation / Answer

moles of acetic acid --> from the mass

MW of acetic a id = 60 g/mo

mol = mass/MW = 1.113/60 = 0.01855 mol of acetic acid

b)

mol of isopentyl alcohol

MW of  isopentyl alcohol = 88.148 g

mol = mass/MW = 0.813/88.148 = 0.00922 mol

Q3.

if ratio is 1:1 then

0.01855 /0.00922 = 2x1 ratio is 2 mol of acetic acid per 1 mol of isopentyl alcohol, the lacohol is limiting

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