0 A 15.0 g bullet is fired at 576.1 m/s into a solid cylinder of mass 23.1 kg an

Question

0 A 15.0 g bullet is fired at 576.1 m/s into a solid cylinder of mass 23.1 kg and a radius .49 m. The cylinder is initially at rest and is mounted on fixed vertical axis that runs through it's center of mass. i aXis cylinder The line of motion of the bullet is perpendicular to the axle and at a distance 9.80 cm from the center. Find the angular velocity of the system after the büllet strikes and adheres to the surface of the cylinder. 40.76 rad/s The angular momentum before and after the collision is the same with respect to the axis

Explanation / Answer

given mass of bullet, m = 0.015 kg
speed, u = 576.1 m/s
cylinder mass M = 23.1 kg
radius R = 0.49 m
d = 0.098 m

from conservation of angular momentum
mud = (mR^2 + 0.5MR^2)w ( where w is final angular speed)
0.015*576.1*0.098 = (0.015 + 0.5*23.1)*0.49^2 *w
w = 0.30498 rad/s

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