Use the following atomic weights and quantities to calculate the overall % yield

Question

Use the following atomic weights and quantities to calculate the overall % yield of stilbene dibromide. Remember that your yield must be based on the limiting reagent, and that grams must be converted to moles. Filling out most of the chart will help. Give only two significant digits in your answer. If after rounding the answer is a whole number, do not include a decimal point C = 12, H 1, N-14, Br 80 stilbene+ pyridium hydrobrom ide perbromide stilbene dibromide formula formula weight grams4.557 moles 5.021 3.788 % yield Answer

Explanation / Answer

Molar mass of stilbene = 180 g/mole

Molar mass of pyridinium hydrobromide perbromide = 320 g/mol

Molar mass of stilbene dibromide = 340 g/mole

Number of moles of a substance = mass/ molar mass

Number of moles of stilbene = 4.557/180 = 0.0253 moles

Number of moles of pyridinium hydrobromide perbromide = 5.021/320 = 0.0156 moles

One mole stilbene reacts with one-mole pyridinium hydrobromide perbromide

Thus limiting reagent is pyridinium hydrobromide perbromide.

The amount of product formed = 0.0156 moles

mass of product = number of moles x molar mass = 0.0156 x 340 = 5.334 g

Actual yield = 3.788 g

% of yield = (3.788/5.334)100 = 71.01 %

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