MyMathLab _ MAT HIS 106 presentati C Secure https/courses hamptonuedu/webapps/as

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MyMathLab _ MAT HIS 106 presentati C Secure https/courses hamptonuedu/webapps/assessment/take/aunch jsp)'course asessment d At Tutor Matching e xanoines x -01.201 at e 43.43 QUESTION 8 Sodium hydroxide reacts with carbon dioxide as follows 2NaOH+ CO2 Na2CO3+H20 What is the limiting reagent when 1.5 mol CO2 and 4.0 mol NaOH are allowed to react? (Answer sodium hydroxide QUESTION 9 Remaining Time: 12 seconds. Sodium hydroxide reacts with carbon dioxide as follows: 2NaOH + CO2 Na2CO3 + H2O The reaction is using 1.5 mol CO2 and 4.0 mol NaOH. How many moles of Na2Cos can be produced? (Ony pe the n Question Completion Status: QUESTION 10 Sodium hydroxide reacts with carbon dioxide as follows 2NaOH+CO2 Na2CO3+ H20 The reaction is using 1.5 mol Co2 and 4.0 mol NaOH. How many moles of the excoss reactant remain after the compler OType here to search

Explanation / Answer

Q8

if

mol of CO2 = 1.5

mol ofNaOH = 4

ratio is: 2:! so

4 mol of NaOh forms ---> 2 mol of Na2CO3

1.5 mol of CO2 forms = 1.5 mol of Na2CO3

clearly, CO2 limits reaciton, since only produced 1.5 mol of Na2CO3

then

choose CO2 as limiting reactant

Q9

from previous data

CO2 has a

1 mol of CO2 = 1 mol of Na2CO3

then

1.5 mol of CO2 = 1.5 mol of Na2CO3

Q10

findmoles of exces NaOH left

1.5 mol of CO2 required = 2x(1.5 ) = 3 mol of NaOH

NaOH left = 4-3 = 1 mol of NaOH

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