How many milliliters of 0.210 M BaCl 2 must be added to 12.4 mL of 0.418 M Na 2

Question

How many milliliters of 0.210 M BaCl2 must be added to 12.4 mL of 0.418 M Na2SO4 to give complete reaction between their solutes? Volume of Ba2+ solution?

One of the solids present in photographic film is silver bromide, AgBr. Suppose we want to prepare AgBr by the following precipitation reaction.
2AgNO3(aq) + CaBr2(aq) 2AgBr(s) + Ca(NO3)2(aq)
How many milliliters of 0.123 M CaBr2 solution must be used to react with the solute in 51.1 mL of 0.160 M AgNO3?

A 15.0 mL sample of vinegar, containing acetic acid, was titrated using 0.549 M NaOH solution. The titration required 20.5 mL of the base.

What was the molar concentration of acetic acid in the vinegar?

Explanation / Answer

Ans 1.

Th balanced reaction is

BaCl2 + Na2SO4 = Ba2SO4 + 2NaCl

An equimolar concentration of bothe the reactants is required for the complete reaction .

So we can use the formula ,

M1V1 = M2V2

Where M is the molarity and V is the volume

putting the values we get ,

0.210 x V1 = 0.418 x 12.4

V1 = 24.68 mL

So 24.68mL of the BaCl2 solution is required.

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