A group of acids arranged in order of decreasing acidify is: HNO_3 > CH_2COOH >

Question

A group of acids arranged in order of decreasing acidify is: HNO_3 > CH_2COOH > C_4H_2OH > H_2O > HC_infinity CH What is the arrangement order conjugate bases these compounds in decreasing order of basicity? No prediction of relative base strength is possible. Why cannot one determine the relative acid strengths of HCIO_4 and HNO_4 using aqueous solutions of these acids? A more basic solvent than H_O must be used. H_2O is too basic a solvent for the distinction to be made. the acid strengths determined using aqueous solutions. The acids are insufficiently soluble These oxidizing acids cause redox reactions to occur, As a consequence of the "leveling effect" the strongest acid which can exist in HNO_3 HCI H_2SO_4 H_2O^+ HCIO_4 A product of the reaction, CH_2CH_2Li + D_2O is Which acid-base reaction would not take place written?

Explanation / Answer

40) The answer is B

   HC=C- > OH- > C3H7O- > CH3COO- > NO2-

This is the opposite order of the corresponding acid strength. This is because, stronger the acid faster it will dissociate thus gives proton to form their conjugate base which will be a poor H+ acceptor. So relatively, in general stronger the acid weaker its conjugate base.

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