A fertilizer contains 12.5 % ammonium nitrate. 20.3 % ammonium sulfate and 11.4%

Question

A fertilizer contains 12.5 % ammonium nitrate. 20.3 % ammonium sulfate and 11.4% urea [CO(NH_2)_2] by mass. How many grams of Nitrogen are present in 1.00 kg bag of this fertilizer? A solution of nickel (II) chloride is mixed with one of ammonium chromate. Write a balanced net ionic equation for this precipitation reaction, showing all phases. The Tollen's test for the presence of reducing sugars (say, in a urine sample) involves treating the sample with silver ions in aqueous ammonia. The result is the formation of a silver mirror within the reaction vessel if a reducing sugar is present. Using glucose to illustrate this test, the redox reaction occurring is C_6 H_12 O_6 (aq) + 2 Ag^-1 (aq) + 2OH^-1 (aq) C_6 H_12 O_7 (aq) + 2 Ag(s) + H_2 O(I) What has been oxidized? What has been reduced? What is the oxidizing agent? What is the reducing agent? Show/explain how you derived your answer.

Explanation / Answer

3)

From the given data

100 g of fertilizer contains

12.45 g NH4NO3

20.3 g (NH4)2SO4

11.4 g (NH2)2CO

So 1000 g = 1 Kg fertilizer contains

124.5 g NH4NO3

203 g (NH4)2SO4

114 g (NH2)2CO

Molar mass of NH4NO3 = 80.043 g/mol

Molar mass of (NH4)2SO4 = 132.14 g/mol

Molar mass of (NH2)2CO = 60.06 g/mol

Atonic mass of nitrogen = 14.007 g /mol

80.043 g ofNH4NO3 contains 28.014 g N

Hence 124.5 g NH4NO3 contains (28.014 ×124.5)/80.043 = 43.57 g N

132.14 g of (NH4)2SO4 contains 28.014 g N

Hence 203 g( NH4)2SO4 contains (28.014 ×203 g)/132.14 = 43.04 g N

60.06 g of urea contains  28.014 g N

Hence 114 g CO (NH2)2 contains (28.014 ×114 g )/ 60.06 = 53.17 g N

Total nitrogen in the bag = 43.57 g + 43.04 g + 53.17 g = 139.78 g

4)

NiCl2(aq) + (NH4)2CrO4(aq) -----------> NiCrO4 (s) + 2 NH4Cl (aq)

5)

Here equation is

C6H12O6 (aq) + 2 Ag+1(aq) + 2 OH-1(aq) ----------> C6H12O7(aq)

+ 2 Ag (aq) + H2O(l)

* Oxidized species is C6H12O6.

Oxidation is also described as addition of oxygen. Here C6H12O6 is oxidized to C6H12O7.

* Reduced species is Ag+1.

Reduction is described as decrease in oxidation number . Here  Ag+1 is reduced to Ag.

* Oxidizing agent is  Ag+1.

Oxidizing agent helps oxidation but itself get reduced.

* Reducing agent is  C6H12O6.

Reducing agent helps reduction but itself get oxidation .

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