A felt covered wooden block with a force sensor mountedon it sits on a metal tra

Question

A felt covered wooden block with a force sensor mountedon it sits on a metal track. The mass of the block with the sensoris 0.96 kg. The force sensor reading is 3.5N as the cart is movingacross the track. The acceleration of the the block is 0.8155m/s2. Calculate the coefficient of kineticfriction mk of theblock, be sure to clearly state the values ofFapplied(N), Fk(N), and the Normal Force(N). If the coefficient of kinetic friction cannont be determinedfrom the given information state why. Hint: Use Ftotal = ma and Ftotal =Fapplied-fk to determine the force ofkinetic friction fk. The coefficient of kineticfriction mk can then be foundfrom fk = mkN. A felt covered wooden block with a force sensor mountedon it sits on a metal track. The mass of the block with the sensoris 0.96 kg. The force sensor reading is 3.5N as the cart is movingacross the track. The acceleration of the the block is 0.8155m/s2. Calculate the coefficient of kineticfriction mk of theblock, be sure to clearly state the values ofFapplied(N), Fk(N), and the Normal Force(N). If the coefficient of kinetic friction cannont be determinedfrom the given information state why. Hint: Use Ftotal = ma and Ftotal =Fapplied-fk to determine the force ofkinetic friction fk. The coefficient of kineticfriction mk can then be foundfrom fk = mkN.

Explanation / Answer

From Newton's laws    Fnet = Fapp - fk        ma = Fapp - kmg        k mg = Fapp -ma         k = (Fapp - ma ) / mg = 3.5 - (0.96)(0.8155) / (0.96) (9.8) =0.288

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.