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Match the fraction type with the equation. Letters may be used more than once. 2

ID: 535579 • Letter: M

Question

Match the fraction type with the equation. Letters may be used more than once. 2 C_2H_2(g) + 5 O_2(g) rightarrow 4 CO_2(g) + 2 H_2O(g) A. Acid/Base Pb(NO_3)_2(aq) + 2 NKr(aq) rightarrow KNO_3(aq) + PbBr_2(s) B. Single Replacement HCl(aq) + H_2SO_4(aq) rightarrow K_2SO_4(aq) + 2 H_2O(l) D. Double Replacement AgC_2H_3O_2(q) + Bal(aq) rightarrow NaC_2H_3O_2(aq) + Agl(s) E. Combination Fe_2O_3(s) + 2 Al(s) rightarrow 2 Fe(l) + Al_2O_3(s) C_2H_2(g) + 2 Cl_2 (g) rightarrow C_2H_2Cl_4(g) Fill in the blanks in the following table. Oxalic acid (H_2C_2O_4) is weak acid found in the leaves of rhubarb. Which of the following solutions will have the highest pH? a) 1.0 M H_2C_2O_4 b) 1.0 times 10^-4 M H_2C_2O_4 c) 0.5 M H_2C_2O_4 d) 0.00075 M H_2C_2O_4 Consider the following reactions: a) Circle which reactant is the acid: 2 K_3PO_4 + 3 H_2SO_4 2 H_3PO_4 + 3 K_2SO_4 b) Circle which reactant is the base: H_2CO_3 + 2NaOH rightarrow 2HOH + Na_2CO_3

Explanation / Answer

Hi

11) Hydrocarbon is burnt in presence of oxygen hence it is a combustion reaction.

12) Double Replacement

13) HCl is an acid and NaOH is a bse, hence it is a acid base reaction.

14) KOH is a base amd H2SO4 is an acid, hence it is a acid base reaction.

15) Double Replacement

16)Single Replacement

17) Combination

Thank you

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