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Bookmarks Window Help saplinglearning.com Organic Che IR Infrared Sp... Courses val... Unit 2 (Ch 12... 06/13/2017 11:ss PM G1.3/s Print Calculator Periodic Table Question 1 of 21 Sapling earning A HNMR signal is observed at 1830 Hz (downfield of TMs) on a 105 MHz instrument. a)Whatisthe observed chemical shift in parts per million (ppm? b) What is he chemical shir, in parts per maon ppm. the sample is analyzed with a 600MHz c) where will the proton signal appear, in hertz, irthe sample is analyzed with a 60 oMHz instnumert? introduction t Gradebook O Te

Explanation / Answer

For the given data.

a) chemical shift in ppm = 183/105 = 1.74 ppm

b) On a 60 MHz instrument, chemical shift would be,

= 183/60

= 3.05 ppm

c) The signal in Hz when 60 MHz instrument is used,

= 1.74 x 60

= 104.4 Hz

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