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Bookmarks People Window Help x C Please Answer This probier x wileyplus.com/edugen/student/mainfr.uni actice Assignment Gradebook ORION PRINTER VERSION FULL SCREEN Question 23 if a random sample 41 produces 126.4 and s 22.6, what is the 98% confidence interval for u? Assume x is normally of items distributed for the population. What is the point estimate? Appendix A Statistical Tables (Round your answer to 1 decimal place.) Question Attemptst of 2 used SAVE FOR LATER Copyright e 2000-2016 by John Wiiey Sons, inc. or related companies. Ai rohts reserved. All Rights Reserved, A Division of lahn gliloussanains, Version 4.17 aglist unlaN101BA

Explanation / Answer

a)

Note that              
Margin of Error E = z(alpha/2) * s / sqrt(n)              
Lower Bound = X - z(alpha/2) * s / sqrt(n)              
Upper Bound = X + z(alpha/2) * s / sqrt(n)              
              
where              
alpha/2 = (1 - confidence level)/2 =    0.01          
X = sample mean =    126.4          
z(alpha/2) = critical z for the confidence interval =    2.33          
s = sample standard deviation =    22.6          
n = sample size =    41          
              
Thus,              
Margin of Error E =    8.223797954          
Lower bound =    118.176202          
Upper bound =    134.623798          
              
Thus, the confidence interval is              
              
(   118.176202   ,   134.623798   ) [ANSWER]

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b)

The point estimate is the sample mean, so

point estimate = 126.4 [ANSWER]

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