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Which of the following orbital diagram is incorrect because it violates Hund\'s

ID: 535235 • Letter: W

Question

Which of the following orbital diagram is incorrect because it violates Hund's rule? Which of the following best represents the reaction between hydrochloric acid and sodium hydroxide? (A) HCl_2, + 2Na(OH)_2 rightarrow 2H_2 O + 2NaCl + OH (B) 2HCl + 2KaOH rightarrow Na(OH)_2 rightarrow H_2 Cl_2 (C) 2HC1 + Na(OH)_2 rightarrow 2H_2 + Na^+ + Cl + O_2 (D) HCl + NaOH rightarrow H_2 O + NaCl How many moles of aluminum are equivalent to 822 times 10^23 atoms of aluminum? (A) 1.36 times 10^23 moles (B) 3.04 times 10^22moles (C) 1.36 moles (D) 0.132 moles According to Boyles' Law, the volume of a fixed amount of gas is inversely proportional to - (A) kelvin temperature (B) pressure (C) boiling point (D) density

Explanation / Answer

46. According to Boyle's law: At constant temperature the volume of a fixed amount of gas is inversely proportional to its pressure.

Hence option B is the correct answer.

45. 1 mol of Al contains - 6.023x10^23 atoms

                ? mols Al       - 8.22x10^23 atoms

= 1mol x 8.22x10^23 atoms/ 6.023x10^23 atoms

= 1.36 mol

Hence, option C is the correct answer.

44. 1 mol of HCl reacts with 1 mol of NaOH and form 1 mol of NaCl and 1 mol of water.

The chemical reaction is as shown below:

HCl + NaOH -> NaCl + H2O

Hence option D is correct.

This reaction is an example of neutralisation reaction.

43. According to Hund's rule, the pairing of electrons in the degenerate orbitals takes place only after each degenerate orbital filled with single electron.

1s orbital can accomodate for maximum for two electrons.

2s orbital can accomodate for maximum for two electrons.

In 2p- subshell three orbitals are there.

First each orbital is filled with single electron then pairing takes place according to Hund's rule.

2px1 2py1 2pz1

then pairing should take place.

Hence, option C is the correct answer which represents the violation of Hund's rule.

42. Mass of crucible + hydrated salt - 31.5g

                 crucible + anhydrous salt - 29.29g

mass of water of hydration =( 31.5-29.29 )g

                                           = 2.21g

Hence % of water in the compound is - (2.21g/31.5g ) x100

                                                             = 7.02%

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