The correct answer is given in bold (C, since the equilibrium position will not

Question

The correct answer is given in bold (C, since the equilibrium position will not be affected, the concentration of CO will remain the same). I do not understand why it is correct though. How do you tell which way the shift is? (Both written and mathematical explanations are great). Thanks!

7. Consider the following reaction at equilibrium: As406 (s) 6 C (s) As4 (g) 6 CO (g) Suppose solid tetraarsenic hexoxide (As406) is added. How does the concentration of carbon monoxide (CO) change? a Since the equilibrium shifts to the right, the concentration of CO will increase. b) Since the equilibrium shifts to the left, the concentration of CO will decrease. c) Since the equilibrium position will not be affected, the concentration of CO will remain the same.

Explanation / Answer

pure solid and pure liquid are not part of equilibrium constant expression

Kc for the given reaction can be written as:

Kc = [AS4][CO]^6

So, [As4O6] will not effect the equilibrium

This is the reason,

Answer is C

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