1.A sample containing the following four alcohols was analyzed by gas chromatogr

Question

1.A sample containing the following four alcohols was analyzed by gas chromatography.

Alcohol           weight (g)        weight %         peak area (cm2)          

n-butyl 0.1731             24.61               3.023

i-butyl             0.1964             27.92               3.074

s-butyl 0.1514             21.52               3.112

t-butyl             0.1826             25.96               3.004

An unknown sample containing only two of the four alcohols was run on the same column. The i-butyl and s-butyl alcohols have peak areas of 3.753 and 2.845 cm2 respectively. What is the weight percent of these two alcohols in the unknown?

Explanation / Answer

1. A. gas chromatography os the alcohols

Known sample of i-butyl area = 3.074 for 27.92 %

So,

unknown sample i-butyl area = 3.753

corressponds to = 3.753 x 27.92/3.074

                           = 34.10 % weigth percent

unknown sample s-butyl area = 3.112

corressponds to = 2.845 x 21.52/3.112

                           = 19.67 % weigth percent

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