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what heat change takes place when an equilibrium system of 2.0 grams of ice and

ID: 530395 • Letter: W

Question

what heat change takes place when an equilibrium system of 2.0 grams of ice and 3.0 grams of water at 0 degrees Celsius is converted entirely to ice at 0 degrees Celsius? (heat of fusion of ice =334 J/g) what heat change takes place when an equilibrium system of 2.0 grams of ice and 3.0 grams of water at 0 degrees Celsius is converted entirely to ice at 0 degrees Celsius? (heat of fusion of ice =334 J/g) what heat change takes place when an equilibrium system of 2.0 grams of ice and 3.0 grams of water at 0 degrees Celsius is converted entirely to ice at 0 degrees Celsius? (heat of fusion of ice =334 J/g)

Explanation / Answer

It is said that entire mixture ( ice + water ) has to be converted to ice at 0 0C.

So already we have 2.0 grams of ice at 0 0C. So only 3.0 grams of water at 0 0C has to be converted to ice at 0 0C.

Heat that is to be removed i.e., latent heat of fusion = m Lf = 3.0 * 334 = 1002 J = 1.002 kJ.