Balance the redox reaction: IO_3^- I_2 When you balance the reaction, the number

Question

Balance the redox reaction: IO_3^- I_2 When you balance the reaction, the number of electron in the balanced half reaction is: A. 9 electron in the left B 5 electron in the right C. 2 electron in the right D. 5 electron in the left E. 10 electron in the left Determine the entropy change for melting 18.0 g ice at the normal melting point. The enthalpy of fusion for water is 6.0 kJ/mol. The solubility of CrF_3 in water is 0.50 g/L at 25 degree C. Determine the solubility product constant for CrF_3. Which of the following is true for Galvanic cell? A. delta G > 0. K >1 B. delta G > 0. E > 0 C. delta G 1 D. delta G H > Cu > Ag > Au .... Which is true? A. Na is the weakest oxidizing agent B. Au is the strongest reducing agent C. Na is the strongest oxidizing agent D. Ag will produce H_2 gas with acids E. Fe will reduce Mg How does the entropy changes in each of the following cases? (increase, decrease, no change) a. NaCl crystal is formed from a solution _____ b. Solid iodine undergoes sublimation ______ c. N_2 (g) + H_2 (g) NH_3 (g) ______ d. CuSO_4 crystals are dissolved in water _______ e. KCIO_3 (s) KCI (s) + O_2 (g) _____ You may use the following information in solving any problem in the exam. Standard reduction potential values: (delta H degree values: C_5 H_12 (g) = -320 kJ/mol; CO_2 (g) = -390 kJ/mol; H_2 O (I) = - 285 kJ/mol) R = 0.08205 L atm/mol.k; R = 8.314 J/mol.k; F = 96481 C/mol e;

Explanation / Answer

Ans 14. E . 10 electrons in the left

In IO3- iodine has an oxidation state of +5 , and in I2 the oxidation state is 0

So start balancing by the number of iodine first , by multiplying IO3- by 2.

So now there is a net +10 charge on the left and 0 on right.

Balance the charges by adding 10 electrons on the left.

Related Questions

Navigate

• Browse (All)
• Browse B
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.