can someone please help me with the right answer for the following questions. ca

Question

can someone please help me with the right answer for the following questions. can you please answer all of them or dont attempt to answer. thank you.

19. The sodium ion content of a urine sample was determined by using an ion- selective electrode. The following values were obtained: 102, 97, 99, 98, 101 and 106 mMe What are the mean and standard deviation of these data? A. Mean 101 mM, standard deviation 3 mM B. Mean 110 mM, standard deviation 3.3 mM C. Mean 100.5 mM, standard deviation 3.27 mM D. None of the above. 20. Using the data from question 19 what are the 95% confidence limits for the sodium ion concentration? A. 100.5 3.4 m B. 100.5 t 5.4 m C. 100.5 3.27 mM D. 1001 3 mM Questions 21-24 are based on the information in the table below. A standard sample of pooled human blood serum contains 42.0 g of albumin per litre. Five laboratories (Alpha Epsilon) each carry out six determinations (on the same day) of the albumin concentration with the following results (g/L). 42.2 Alpha 42.5 42.1 Beta 39.8 43.6 42.1 40.1 43.9 Gamma 43.5 42.8 43.8 43.2 42.7 35.0 43.0 37.1 40.5 36.8 42.2 Epsilon 41.6 42.0 41.8 42.6 39.0 21 Which laboratories produced the most accurate mean value? A. Alpha and Beta B. Alpha and Gamma C. Beta and Gamma D. Gamma and Epsilon 22. Which laboratory produced the most precise data? A. Beta B. Epsilon C. Alpha D. Gamma

Explanation / Answer

19. Ans is "c"

Mean= 100.5mM and std deviation = 3.27 mM

Solution: Xi

total:603 53.5

Xmean= Xi/n

            = 603/6= 100.5mM

Std dev

s = (xi - x) 2 /(n - 1)

     =53.5/5 = 10.7= 3.27mM

for 20 ans is "A"

x ± t(n-1s)/2n

the value of t for calculating the 95% confidence limits is 2.57 so the 95% confidence limits of the mean are given by:

100.5 ±2.57 x 3.27/26 = 100.5 ± 3.4 mM.

Xi Xi-Xmean (Xi-Xmean)2 102 1.5 2.25 97 -3.5 12.25 99 -1.5 2.25 98 -2.5 6.25 101 0.5 0.25 106 5.5 30.25

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