Select the reaction that will occur spontaneously, using Table 15.3. Cu (s) + 2

Question

Select the reaction that will occur spontaneously, using Table 15.3.

Cu(s) + 2 Ag+(aq) Cu2+(aq) + 2 Ag(s)

The following reaction takes place in an alkaline battery:
Zn(s) + 2MnO2(s) ZnO(s) + Mn2O3(s)
Which of the following half-reactions occurs at the cathode?

Cu(s) + Zn2+(aq) Cu2+(aq) + Zn(s) Cr(s) + Al3+(aq) Cr3+(aq) + Al(s) Sn(s) + Mg2+(aq) Sn2+(aq) + Mg(s)

Cu(s) + 2 Ag+(aq) Cu2+(aq) + 2 Ag(s)

The following reaction takes place in an alkaline battery:
Zn(s) + 2MnO2(s) ZnO(s) + Mn2O3(s)
Which of the following half-reactions occurs at the cathode?

Zn(s) + 2OH (aq) ZnO(s) + H2O(l) + 2e 2MnO2(s) + H2O(l) + 2e Mn2O3(s) + 2OH (aq) 2MnO2(s) Mn2O3(s) Zn(s) ZnO(s) TABLE 15.3 Activity Series for Some Metals lon Most active Li(s) Li (ag) E oxidize easily K (ag) e K(s) Cat (ag) 2 Ca(s) Nat(ag) Na(s) Mg(s) Mg (ag) 2 Al(s) Als (aq) 3 zn2 (aq) 2e Zn(s) Crs+(ag) 3 en Cr(s) Re(s) Fe (aq) 2 Ni(s) Sn(s) (g) 2H (aq) 2 er Cu (ag) 2 Cu(s) ARG) Ag (aa) e Least active Au (aq) 3 e Au(s) oxidize with difficulty

Explanation / Answer

* (d) Cu(s) + 2 Ag+ (aq.) ----------> Cu2+ (aq.) + 2 Ag(s)

Because this reaction gives positive E0cell value where as remaining gives negative E0cell value.

E0cell = E0Ag+/Ag - E0Cu2+/Cu = 0.800 - 0.342 = + 0.458 V

**

At cathode reduction reaction takes place that gaining of electrons is occured.

So,

(b) 2 MnO2 (s) + H2O (l) + 2 e --------> Mn2O3 (s) + 2 OH- (aq.)

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