R = 8.314 J/molK = 1.987 cal/molK delta G degree= -RT1nK_aq pH = pK_a + log [c.b

Question

R = 8.314 J/molK = 1.987 cal/molK delta G degree= -RT1nK_aq pH = pK_a + log [c.b]/[c.a] log (Y/1 - Y)(-or- log theta) = n_HlogK_d + n_Hlog[L] Hill equation. The amino acid gamma-carboxyglutamic has four ionizable groups with the following pKa values: pK_COOH = 1.71, pK_amino = 9.9, pK_P groupCOOH = 3.2, and Pk_P groupCOOH = 4.76. What would be its approximate isoelectric point? 2.5 4.0 7.3 9.7 12 Which of the following protein extracts has the highest specific activity? Which bond in a polypeptide chain has partial double bond character? C alpha - C = O O = C - N N - C alpha C alpha -- H

Explanation / Answer

Q-3

here 4 pka values are given in that case the side ionic group moves the Ip to more acidic side,

so it will be = Pkcooh + PkRcooh /2   

= 1.71 + 3.2 /2

= 2.5

Q.5 specific activity = activity/ wt x 100

this value is greater for option b that is

= 80000/200 x 100 = 40000

Q.7 the C-N as option b is correct because the lone pair at nitrogen is in conguation with C=O group, gives it partial double bond character.

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