Sodium nitrate has s solubility of 80.5 g NaNO_3/100.0 g of H_2O at 10 degree C.

Question

Sodium nitrate has s solubility of 80.5 g NaNO_3/100.0 g of H_2O at 10 degree C. The solubility of NaNO_3 increases as the temperature of solution increase Identify which statements about sodium nitrate solutions are true by checking the box in front of each true statement. A solution containing 25.0 g of NaNO_3 dissolved in 25.0 g of H_2O at 10 degree C is unsaturated. A solution containing 25.0 g of NaNO_3 dissolved in 50.0 g of H_2O at 10 degree C is unsaturated. 201 g of NaNO_3 can dissolve in 250.0 g of H_2O at 10 degree C. A solution containing 24.0 g of NaNO_3 dissolved in 25.0 g of H_2O at 10 degree C is supersaturated. A solution containing 80.5 g of NaNO_3 dissolved in 100.0 g of H_2O at 10 degree C is supersaturated. A solution containing 80.5 g of NaNO_3 dissolved in 100.0 g of H_2O at 3 degree C is supersaturated.

Explanation / Answer

S =mass/mass oslvnet = 80.5/100 = 0.85 g/g

i)

S = 25/25 = 1, this is gretaer than 0.85, so this is supersaturated

ii)

25/50 = 0.5, this is unsaturated since 0.5 < 0.85

iii)

201/250 = 0.804, this is unsaturated, so this is true

iv)

24/25 0 '0.96

this is supersaturated

v)

this is saturated nly

vi)

if T decreases, then solubility decreases, therefore, the previously saturated solution is now supersaturated

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