If 30.2 mL of 0.0995 M NaOH arc required to titrate 25 mL of a monoprotic acid (

Question

If 30.2 mL of 0.0995 M NaOH arc required to titrate 25 mL of a monoprotic acid (HA) to the endpoint, what is the molar concentration of HA in the titration solution? A. 8.33 M B. 0.120 M C. 1.32 times 10^-4 D. 0.0824 M E. 12.1 M What is the K_b value for the conjugate base (A^1) from the weak acid HA (K_a - 4.9 times 10^-10)? A. 4.9 times 10^4 B. 5.3 times 10^-1 C. 2.0 times 10^-5 D. 1.0 times 10^14 E. 86 times 10^2 In the oxidation-reduction titration experiment, what was used to standardize the potassium permangana titrant? A. Na_2 C_2 O_4. B. KHP C. H_2 SO_4 D. NaOH E. Standardization was not required Which of the following reactions would be most spontaneous at 298 K? A. A + B rightarrow C; E degree _cell = + 1.22 V B. A + B rightarrow 2 C; E degree _cell = - 0.030 V C. A + 2B rightarrow C; E degree _cell = + 0.98 V D. A + B rightarrow 3 C; E degree _cell = + 0.15 V E. more information is needed to determine,

Explanation / Answer

37)

Balanced chemical equation is:

1 NaOH + 1 HA ---> 1 NaA + 1 H2O

According to balanced reaction:

1*number of mol of NaOH =1*number of mol of HA

1*M(NaOH)*V(NaOH) =1*M(HA)*V(HA)

1*0.0995*30.2 = 1*M(HA)*25.0

M(HA) = 0.120 M

Answer: B

38)

use:

Kb = E-14/Ka

Kb = (1.0*10^-14)/4.9E-10

Kb = 2.0*10^-5

Answer: C

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