If 20.0g of magnesium react with excess hydrochloric acid, how many grams of mag

Question

If 20.0g of magnesium react with excess hydrochloric acid, how many grams of magnesium chloride are produced? Hydrogen gas is also produced in this reaction. How many grams of chlorine gas must be reacted with excess sodium iodide if 10.0g of sodium chloride are needed? Solid iodine is also produced in this single displacement reaction. How many grams of oxygen are produced in the decomposition of 5.00g of potassium chlorate? Potassium chloride is also produced in this reaction. What mass of copper(ll) is required to replace silver from 4.00g of silver (l) nitrate? If excess ammonium sulfate reacts with 20.0g of calcium hydroxide to produce calcium sulfate, ammonia, and water, how many grams of ammonia (NH_3) are produced? If excess sulfuric acid reacts with 30.0g of sodium chloride, how many grams of HCI are produced? How much silver (I) phosphate is produced if 10.0g of silver (I) acetate react with excess sodium phosphate in the unbalanced equation: AgCH_3 COO + Na_3 PO_4 rightarrow Ag_3 PO_4 + NaCH_3 COO How many grams of sodium hydroxide are needed to completely neutralize 25.0g of sulfuric acid to form sodium sulfate and water?

Explanation / Answer

1. Mg + 2HCl------> MgCl2 + H2

    1 mole of Mg react with HCl to form 1 mole of MgCl2

    24 g of Mg react with HCl to form 95g of MgCl2

   20g of Mg react with HCl to form = 95*20/24   = 79.16g of MgCl2

2.   Cl2 + 2NaI ------> 2NaCl + I2

2 moles of NaCl produced from 1 mole of Cl2 react with NaI

2*58.5g of NaCl produced from 71g of Cl2 react with NaI

10g of NaCl produced from = 71*10/2*58.5   = 6.068g of Cl2 react with NaI

3. 2KClO3 ------> 2KCl + 3O2

2 moles of KClO3 decomposes to gives 3 moles of O2

2*122.5g of KClO3 decomposes to gives 3*32g of O2

5g of KClO3 decomposes to gives = 3*32*5/2*122.5   = 1.96g of O2

4. Cu + 2AgNO3 -----> Cu(NO3)2 + 2Ag

   2 moles of AgNO3 react with 1 mole of Cu

2*170g of AgNO3 react with 63.5g of Cu

4g of AgNO3 react with 63.5*4/2*170 = 0.747g of Cu

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