consider the reaction of 2.85 timrd10^-2g iron metal (atomic weight 55.85 g/mole

Question

consider the reaction of 2.85 timrd10^-2g iron metal (atomic weight 55.85 g/mole) placed in 100.0 mL of a phosphoric acid solution II** The reaction produce hydrogen molecules and iron(II) phosphate at standard temperature (0 degree C) and pressure (760 atm). Solution I was made by dissolving 10.0 phosphoric acid (MM=98.0 g/mol) in water to a find volume of 100.0 mL **-Solution ll was made by diluting 2.00 mLof solution* to final volume of 0.200 L with water. This reaction would be an example of each of these types of reaction except: an acid-base reaction. a gas-producing reaction. redox reaction. a single displacement. a precipitation reaction. Which of these is the correct balanced equation? Fe_(s) + H_2PO_4_(aq) rightarrow H_2 |g| + Fe{P_4(aq) 2Fe_(s) + 3 H_2PO_4(aq) rightarrow 3 H_2(g) + Fe_2(PO_2)_3(aq) 2 Fe_(s) + 3 H_2PO_4_(aq) rightarrow 3 H_2(g) + Fe_2(PO_4)_3 (s) 3 Fe_(s) + 2 H_2PO_4(aq) rightarrow 3 H_2(g) + Fe_3[PO_4)_2 (g) 2 Fe_(s) + 2 H_3PO_4_(aq) rightarrow 3 H_2(g) + 2 FePO_4(s) You could see when the reaction is over by each of the following except: when no more gas evolved. when all the iron metal dissolved. when no more white precipitate formed when the stoichiometric amount of precipitate formed. You can't fool me! All or none of these are correct! What is the concentration of Solution 1 in M? 0.00102 0, 0102 0.980 1.02 980 What is the concentration of Solution II? 0.00102 0, 0102 0.0980 0.980 1.02

Explanation / Answer

Iron metal + acid --> H2(g) will b eproduced and Fe3+ goes to ionc state

therefore

this is clearly agas producing reaction

AND a redox reaction, sice Fe goes from 0 to +3, nd H goes from +1 to 0

It also forms precipitation, due to the single replacement

so this is NOT acid-base reaction

Q2.

The reaction that best fit:

Fe(s) + H3PO4(aq) -> H2(g) + Fe+3(aq) + PO4-3(aq)

balance H

Fe(s) + H3PO4(aq) -> 3/2H2(g) + Fe+3(aq) + PO4-3(aq)

multiply all by 2

2Fe(s) + 2H3PO4(aq) -> 3H2(g) + 2Fe+3(aq) + 2PO4-3(aq)

2Fe(s) + 2H3PO4(aq) -> 3H2(g) + 2FePO4(s)

best answer is E

Q3.

a is true, if no more bubbles are seen, reaciton is over

b is true, if excess acid is providede, all should go from solid metal to salt

c true

d also true

therefore, choose All, i.e. "E"

Q4.

M = mol/V = (10/98) / (0.1) = 1.02 M

choose E

Q5.

dilution 2 mL to 200 mL

x 100 --> 1.02 /100 = 0.0102

choose B

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