consider the following reaction: 2H2O (g) + 2SO2 (g) <---> 2H2S (g) + 3O2 (g) a
ID: 608746 • Letter: C
Question
consider the following reaction: 2H2O (g) + 2SO2 (g) <---> 2H2S (g) + 3O2 (g) a reaction mixture initially contains 2.8 M H2O and 2.6 M SO2. Determine the equilbirum concentration of H2S if Kc for the reaction at this temperature is 1.3 x 10^-6 Please show your work and explain thank you!Explanation / Answer
Kc= [O2]^3 x [H2S]^2 / [SO2]^2 x [H2O]^2 => H2S = sqrt( Kc x [SO2]^2 x [H2O]^2 /[O2]^2)= sqrt(6.88 x 10^-5 )= 8.3x 10^-3 ////// I will explain everything........ number in front of H2S or O2 or [H2O] will become power of H2S and O2 and SO2 /// like 2H2S will become H2S ^ 2 ( square) and 3O2 will become [O2]^3 (cube of O2) please comment still you didnt understand
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