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2. Carly the chemistry student performs an experiment with vinegar active ingred

ID: 524872 • Letter: 2

Question

2. Carly the chemistry student performs an experiment with vinegar active ingredient acetic acid, CHrcooH) and baking soda (NaHco,). Her professor asks her to place varying amounts of baking soda and vinegar into sealable plastic bags, quickly seal the bags, and observe the reaction. The balanced chemical equation for the reaction is given here. a) Use limiting reagent calculations to fillin the following table. Please show your work. Amount of Trial Baking Vinegar (5% Amount of Amount of Limiting acetic acid) CO2 (mol) if co2 (mol) if reactant CO2 formed soda (mol) baking soda vinegar limiting limiting A 0.25 g 10, mL B 0.75 g 8.0 mL C 1.5 g 5.0 mL b) Which Ziploc bag will inflate the most?

Explanation / Answer

Use the limiting reactant calculation to fill in the following table

TRIAL

Mass of baking soda

Volume of vinegar

(5%)

Mole of co2

I f baking soda limiting

Moles of

carbon

dioxide if

vinegar is

limiting

Limiting

reactant

Moles of

Carbon

dioxide

formed

A

0.25 g

10 ml

0.0030 mol

0.17 mol

Baking soda

0.0030 mol

B

0.75 g

8ml

0.009 mol

0.13 mol

Baking soda

0.0089 mol

C

1.5 g

5 ml

0.018 mol

0.084 mol

Baking soda

0.001mol

Baking soda

a.

0.25g NaHCO3x (1mol NaHCO3/ 84.01 g NaHCO3) x (1 mol CO2/ 1 molNaHCO3) = 0.0030

mol CO2

===============================================================

b.0.75g NaHCO3x (1mol NaHCO3/ 84.01 g NaHCO3) x (1 mol CO2/ 1 molNaHCO3) = 0.0089 mol CO2

===============================================================

c.1.5g NaHCO3x (1mol NaHCO3/ 84.01 g NaHCO3) x (1 mol CO2/ 1 molNaHCO3) = 0.018 mol CO2

Vinegar; density of vinegar is

1.01 g/mL

10 mL x (1.01 g / 1 mL) = 10.10 g

8.0 mL x (1.01 g / 1 mL) = 8.08 g

5.0 mL x (1.01 g / 1 mL) = 5.05 g

a.10.10g HC2H3O2x (1 mol HC2H3O2/ 60.06 g HC2H3O2) x (1 mol CO2/ 1 molHC2H3O2) = 0.17 mol HC2H3O2

b.8.08g HC2H3O2x (1 mol HC2H3O2/ 60.06 g HC2H3O2) x (1 mol CO2/ 1 molHC2H3O2) = 0.13 mol HC2H3 O2

Which bag will inflate the most ? answer BAG C

TRIAL

Mass of baking soda

Volume of vinegar

(5%)

Mole of co2

I f baking soda limiting

Moles of

carbon

dioxide if

vinegar is

limiting

Limiting

reactant

Moles of

Carbon

dioxide

formed

A

0.25 g

10 ml

0.0030 mol

0.17 mol

Baking soda

0.0030 mol

B

0.75 g

8ml

0.009 mol

0.13 mol

Baking soda

0.0089 mol

C

1.5 g

5 ml

0.018 mol

0.084 mol

Baking soda

0.001mol