5. In a population of flowers, the allele for purple petals, P, is dominant to t

Question

5. In a population of flowers, the allele for purple petals, P, is dominant to the allele for white flowers, p. If 84% of the population has purple flowers, what percent of the population are heterozygous if the population is in Hardy-Weinberg equilibrium? cannot tell from the information provided 42% 24% 16% 48% 6.If an allele is recessive and lethal in homozygotes before they reproduce, Q A) the allele is present n the population at a frequency of 0.00 1. B) the allele will be removed from the population by natural selection in approximately 1,000 years. C) The allele will most likely remain in the population at a low frequency because it cannot be selected against n heterozygotes. D) the fitness of the homozygous recessive genotype is 0. E) both C and D are correct 7.For a population to be in Hardy-Weinberg equilibrium it must satisfy all of the following conditions EXCEPT: no mutations no random mating no natural selection no genetic drift no gene flow 8. In a flock of sheep, 4 percent of the population has white wool and 96 percent has black wool. Assume that the population is in Hardy-Weinberg equilibrium. If white wool is a recessive trait, what percentage of the population is heterozygous for this trait? 4% 20% 32% 64% 80%

Explanation / Answer

Answer:

5) 48%

84/100= 0.84

q2= 0.16

q= 0.4

p =0.6, q =0.4

According to hardy weinberg

p2+2pq+q2

2pq = 0.48*100= 48%

6) E

7) no random mating

Mating should takes place in hardy weinberg population

8), 32 %

q^2 = 0.04

q = 0.2

so, p= 0.8

According to hardy weinberg

p2+2pq+q2

2pq= 2x0.2 x 0.8= 0.32

32%

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