Where R is the gas constant (8.314 J deg^-1mol^-1), T is the absolute temperatur
ID: 520224 • Letter: W
Question
Where R is the gas constant (8.314 J deg^-1mol^-1), T is the absolute temperature (37 degree C = 310 degree K). F is the Faraday's constant (96500 C mol^-1); z is the valence for the ion: E is in volts (V). Calculate: (a) If a membrane is permeable to Na^+ ions only, what is the equilibrium potential for Na^+: for z = 1? (b) If a membrane is permeable to K^+ ions only, what is the equilibrium potential for K^+: for z = 1? (c) if a membrane is permeable to Ca^+ + ions only, what is the equilibrium potential for Ca^++: for z = 2? (d) If a membrane is permeable to Cl^+ions only, what is the equilibrium potential for Cl: for z = -1? If the temperature of the neuron is changed from 37 degree C (body temperature for mammals) to 25 degree C (for marine animals), what would be the corresponding E_Na. E_k, E_Ca, E_Cl? If a membrane is permeable to both Na^+ and K^+ ions, what is the equilibrium potential (also called reversal potential), which is given by E = RT/F log, P_na [Na^+]_ + P_k [K^+]/P_na [Na^+]_ + P_k [K^+], assuming P_na = P_k?Explanation / Answer
Answer.1. a) Equilibrium potentiial ENa =( RT/zF) loge [Na+ ]ext / [Na+ ]in
ENa = (8.314x310/1x96500) loge [150/15]
ENa = 2577.34/96500 loge 10 = 0.027x2.302
ENa =0.062 V
b) Equilibrium potentiial EK =( RT/zF) loge [K+ ]ext / [K+ ]in
Ek = (8.314x310/1x96500) loge [5.5/150]
Ek = 0.027 xloge 0.037
Ek = 0.027 x (-3.3)
Ek = - 0.75 V
c) Equilibrium potentiial ECa =( RT/zF) loge [Ca+2 ]ext / [Ca+2 ]in
ECa = (8.314x310/2x96500) loge [1/10-4]
ECa = 2577.34/(2x96500) x4xloge 10
ECa = 0.013x4x2.302
ECa =0.25 V
d) Equilibrium potentiial ECl-=( RT/zF) loge [Cl- ]ext / [Cl- ]in
ECl-= (8.314x310(/-1)x96500) loge [125/9]
ECl-= - 0.027x2.63
ECl-= - 0.071 V .
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