Both Colbat and Cesium emit gamma rays. Which source had the LEAST energetic gam

Question

Both Colbat and Cesium emit gamma rays. Which source had the LEAST energetic gamma ray?
Suppose the Penetration factor for the Cobalt gamma rays in tungsten is 2.3 cm-1. Then how many centimeters of tungsten are needed to block 85% of the gamma rays from a Cobalt source?
Please help me answer all of these, I'm very confused 1) All three of the radioactive sources emitted B particles. The enery of the B particles is not constant and varies between the three sources. The energy of the B particle correlates with the penetration power of the B with higher energy beta particles having the greatest penetration power. Based on your graphs, the B particle from which of the three radiation sources has the MOST energy? Justify your answer. Both "Co and "cs emit gamma rays. Which source had the LEAST energetic gamma raay? Justify your answer suppose the penetration factor for the "co gamma ray in tungsten is 23 cm Then how many cm oftungsten are needed to block 85% ofthe gamma rays from a co source? 4) If sr undergoes beta decay, then what is the resulting element and atomic weight ofthe product element after the beta decay has occurred?

Explanation / Answer

Answer to Q4)

In a - decay, a neutron inside the nucleus of an atom breaks down and changes into a proton. It emits an electron and an anti-neutrino and the atomic number adds up by one. However, the mass number remains unchanged. Thus in a - decay, 62He converts to 63Li by emitting a - particle and5226Fe converts to 5227Co by emitting a - particle.

So in the given question,

9038Sr------> 9039Y + - particle

Hence the new element will be yttrium with mass number 90 and atomic number 39.

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