Given the values of H rxn, S rxn, and T below, determine S univ. Part A H rxn= 1
ID: 519389 • Letter: G
Question
Given the values of Hrxn, Srxn, and T below, determine Suniv.
Part A
Hrxn= 118 kJ , Srxn= 252 J/K , T= 304 K .
Part B
Hrxn= 118 kJ , Srxn= 252 J/K , T= 304 K .
Part C
Hrxn= 118 kJ , Srxn= 252 J/K , T= 304 K
Part D
Hrxn= 118 kJ , Srxn= 252 J/K , T= 552 K .
Part E
Predict whether or not the reaction in part A will be spontaneous. (Assume that all reactants and products are in their standard states.)
Part F
Predict whether or not the reaction in part B will be spontaneous. (Assume that all reactants and products are in their standard states.)
Part G
Predict whether or not the reaction in part C will be spontaneous. (Assume that all reactants and products are in their standard states.)
Part H
Predict whether or not the reaction in part D will be spontaneous. (Assume that all reactants and products are in their standard states.)
Explanation / Answer
Part A)
Given Values are
Srxn= -252 J/K = -0.252 KJ/K
Hrxn= 118 kJ
T=304 K
Suniv = ??
now we know the formula
S(surrounding) = -delta (H/T)
= - (118KJ/304K)
= -0.388 KJ/K
Now we know
Suniv = S(surrounding) + S(sys)
so
Suniv = -0.388 KJ/K + (-0.252) KJ/K
= -0.640 KJ/K
= -640 J/K
Part B)
Given Values are
Srxn= 252 J/K = 0.252 KJ/K
Hrxn= 118 kJ
T=304 K
Suniv = ??
now we know the formula
S(surrounding) = -delta (H/T)
= - (-118KJ/304K)
= 0.388 KJ/K
Now we know
Suniv = S(surrounding) + S(sys)
so
Suniv = 0.388 KJ/K + 0.252 KJ/K
= 0.640 KJ/K
= 640 J/K
Part C)
Given Values are
Srxn= -252 J/K = -0.252 KJ/K
Hrxn= 118 kJ
T=304 K
Suniv = ??
now we know the formula
S(surrounding) = -delta (H/T)
= - (-118KJ/304K)
= 0.388 KJ/K
Nowwe know
Suniv = S(surrounding) + S(sys)
so
Suniv = 0.388 KJ/K - 0.252 KJ/K
= 0.136 KJ/K
= 136 J/K
Part D)
Given Values are
Srxn= -252 J/K = -0.252 KJ/K
Hrxn= 118 kJ
T=552 K
Suniv = ??
now we know the formula
S(surrounding) = -delta (H/T)
= - (-118KJ/552K)
= 0.214 KJ/K
Now we know
Suniv = S(surrounding) + S(sys)
so
Suniv = 0.214 KJ/K - 0.252 KJ/K
= -0.038 KJ/K
= -38 J/K
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