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Given the values of H rxn, S rxn, and T below, determine S univ. Part A H rxn= 1

ID: 519389 • Letter: G

Question

Given the values of Hrxn, Srxn, and T below, determine Suniv.

Part A

Hrxn= 118 kJ , Srxn= 252 J/K , T= 304 K .

Part B

Hrxn= 118 kJ , Srxn= 252 J/K , T= 304 K .

Part C

Hrxn= 118 kJ , Srxn= 252 J/K , T= 304 K

Part D

Hrxn= 118 kJ , Srxn= 252 J/K , T= 552 K .

Part E

Predict whether or not the reaction in part A will be spontaneous. (Assume that all reactants and products are in their standard states.)

Part F

Predict whether or not the reaction in part B will be spontaneous. (Assume that all reactants and products are in their standard states.)

Part G

Predict whether or not the reaction in part C will be spontaneous. (Assume that all reactants and products are in their standard states.)

Part H

Predict whether or not the reaction in part D will be spontaneous. (Assume that all reactants and products are in their standard states.)

Explanation / Answer

Part A)

Given Values are

Srxn= -252 J/K = -0.252 KJ/K

Hrxn= 118 kJ

T=304 K

Suniv = ??

now we know the formula

S(surrounding) = -delta (H/T)

= - (118KJ/304K)

= -0.388 KJ/K

Now we know

Suniv = S(surrounding) + S(sys)

so

Suniv = -0.388 KJ/K + (-0.252) KJ/K

= -0.640 KJ/K

= -640 J/K

Part B)

Given Values are

Srxn= 252 J/K = 0.252 KJ/K

Hrxn= 118 kJ

T=304 K

Suniv = ??

now we know the formula

S(surrounding) = -delta (H/T)

= - (-118KJ/304K)

= 0.388 KJ/K

Now we know

Suniv = S(surrounding) + S(sys)

so

Suniv = 0.388 KJ/K + 0.252 KJ/K

= 0.640 KJ/K

= 640 J/K

Part C)

Given Values are

Srxn= -252 J/K = -0.252 KJ/K

Hrxn= 118 kJ

T=304 K

Suniv = ??

now we know the formula

S(surrounding) = -delta (H/T)

= - (-118KJ/304K)

= 0.388 KJ/K

Nowwe know

Suniv = S(surrounding) + S(sys)

so

Suniv = 0.388 KJ/K - 0.252 KJ/K

= 0.136 KJ/K

= 136 J/K


Part D)

Given Values are

Srxn= -252 J/K = -0.252 KJ/K

Hrxn= 118 kJ

T=552 K

Suniv = ??

now we know the formula

S(surrounding) = -delta (H/T)

= - (-118KJ/552K)

= 0.214 KJ/K

Now we know

Suniv = S(surrounding) + S(sys)

so

Suniv = 0.214 KJ/K - 0.252 KJ/K

= -0.038 KJ/K

= -38 J/K

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