Determine the potential of a platinum electrode (vs. SHE) when placed in the fol

Question

Determine the potential of a platinum electrode (vs. SHE) when placed in the following solutions at 25°C.

e Print Calculator Periodic Table Map Sapling Learning macmilan learning Determine the potential of a platinum electrode (vs. SHE) when placed in the following solutions at 25 C. A) A mixture of 0.00317 MTICB and 0.0575 M TICI TINT (aq)+ 2e TI (ag) E' 31.25 V Number 1.21 B) A mixture of 0.0298 M potassium permanganate (KMno4) and 0.0439 M manganese chloride (MnCl2) at pH 5.8 Mnoi (ag) 5e 8H (aq) Incorrect. Number You input the standard reduction potential for the v reduction of Mno4 to Mn You need to use the Nernst 1.504 equation to account for the non-standard conditions and solve for E. AO Previous 8 Give up & View solution a Try Again ONext DIExit

Explanation / Answer

Given that,

[Mn2+] = 0.0439 M

[MnO4-] = 0.0298 M

[H+] = 10-pH = 10-5.8 = 1.58 * 10-6 M

n = 5 e

Q = [Mn2+]/[MnO4-][H+]8

Q = (0.0439)/(0.0298)(1.58*10-6)8

Q = 3.79 * 1050

Therefore, Pllying Nernst equation,

Ecell = E0cell - (0.05916 / n ) LogQ

= 1.51 - (0.05916 / 5) Log (3.79 * 1050)

= 1.16 V

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