Determine the pH change when 0.083 mol HClO 4 is added to 1.00 L of a buffer sol

Question

Determine the pH change when 0.083 mol HClO4 is added to 1.00 L of a buffer solution that is 0.349 M in HCN and 0.338 M in CN-.

pH after addition pH before addition = pH change =

A buffer solution contains 0.333 M NaH2PO4 and 0.221 M Na2HPO4. Determine the pH change when 0.046 mol HClO4 is added to 1.00 L of the buffer.

pH change =

A buffer solution contains 0.263 M CH3NH3Cl and 0.339 M CH3NH2 (methylamine). Determine the pH change when 0.076 mol HNO3 is added to 1.00 L of the buffer.

pH after addition pH before addition = pH change =

Explanation / Answer

(1)

We know the equation to calculate pH of acid buufer as,

pH = pKa + Log[salt]/acid]

pH = 9.1 + Log(0.338/0.349)

pH before addition of strong acid = 6.07

After addition of HClO4,

[Acid] = 0.349 + 0.083 = 0.432 M and [Salt] = 0.338 - 0.083 = 0.255 M

pH = 9.1 + Log(0.255/0.432)

pH after addition of strong acid = 8.87

Therefore,

pH after addition - pH before addition = 8.87 - 6.07 = 2.80

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