A student did an experiment to calculate percent composition of a mixture potass

Question

A student did an experiment to calculate percent composition of a mixture potassium chlorate and Potassium chloride. At the end of the experiment, student determined that the mixture had 71 percent of Potassium chlorate and 39 percent of potassium chloride. Do you think this data make sense? Explain your reasoning A chemist heated an unknown hydrate, MgSO_4, X H_2O, in a crucible. The water was driven off leaving the anhydrous salt the crucible. After cooling, the mass of the and water lost was calculated. The mass of the hydrated salt was 2.5 grams g and the mass of the water lost was 1.1 gram. Is it possible to find the mass of the anhydrous salt? Please show your calculations or explain. What are the three main variables that are involved in Boyle's law. Name them with their correct units. Which one of these three variables that you must convert to its standard unit when solving a problem on gas law.

Explanation / Answer

No it doesn't make sense because sum of percent cant be more than 100

composition cannot be greater than 100

here given as 71 percent and 39 percent

sum = 71 + 39 = 110 which is not possible

Given

mass of hydrated salt = 2.5 g

mass of water lost = 1.1 g

Mass of anhydrous salt = 2.5 g - 1.1 g = 1.4 g Answer

three variables involved are P, V ,k where k is constant k = nRT

boyle's law PV = k

P unit is Pa

V unit is m3

k unit is J

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