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For each element: 1) Write the complete electron configuration for the neutral a

ID: 517456 • Letter: F

Question

For each element: 1) Write the complete electron configuration for the neutral atom 2) Draw out an orbital box diagram showing the distribution of electrons in the atom 3) Characterize the neutral atom as either paramagnetic or diamagnetic. 4) Write quantum numbers for the electrons in the highest energy level of the atom 5) Write the four quantum number for the last electron added to the atom according to the Aufbau principle order discussed in class. A complete electron configuration does not abbreviate closed electronic shells below the valence level using the a noble gas's element symbol in square brackets.

Explanation / Answer

1. Balanced chemical equation

SO2 + 2HNO2 -----> H2SO4 + 2NO

2. Oxidation number

SO2: S = +4, O = -2

HNO2: H = +1, N = +3, O = -2

H2SO4: H = +1, S = +6, O = -2

NO: N = +2, O = -2

3. Sulphur (S) is oxidized as the oxidation number of S in SO2, +4 is increased to +6 in S of H2SO4

4. Nitrogen (N) is reduced as the oxidation number of N in HNO2, +3 is reduced to +2 in N of NO

5. Hreaction=[Hf (Products)][Hf (Reactants)]

H = [Hf (H2SO4) + Hf (2NO)] - [Hf (SO2) + Hf (2HNO2)]

H = [(1 mol X -811.3 kJ/mol) + (2 mol X 90.4 kJ/mol)] - [(1 mol X -296.4 kJ/mol) + (2 mol X -118.8 kJ/mol)]

H = -630.5 kJ + 534 kJ = -96.5 kJ

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