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13 Item 1 em 1 In addition to mass balance, oxidation reduction reactions must b

ID: 516593 • Letter: 1

Question

13 Item 1 em 1 In addition to mass balance, oxidation reduction reactions must be balanced such that the number of electrons lost in the oxidation equals the number of electrons gained in the reduction This balancng can be done by two methods the half reaction method or the oxidation number method. The half. eaction method balances the electrons lost in the oxidation half reaction with the electrons gained in the reduction half reaction. In either method Hao(), OH (aq), and H (aq) may be added to complete the mass balance Which substances are used depends on the reaction conditions previous 1 of 21 l nex Acidic solution In acidic solution, the nitrate ion can be used to react with a number of metal ions. One such reaction is NO (aq) +Sn? (aq)- NO2(aq) Sn (aq) Since this reaction takes place in acidic solution, H20() and H (aq) will be involved in the reaction. Places for these species are indicated by the blanks in the following restatement of the equation NO's (aq) Sna (aq) Part A What are the coefficients of the reactants and products in the balanced equation above? Remember to include H20 and H (aq) in the appropriate blanks. Your answer should have six terms Enter the equation coefficients in order separated by commas (e.g., 2,2,1,4,4,3) nclude coefficients of 1, as required, for grading purposes. Submit Hints My Answers Give Up Review Part Basic solution Potassium permanganate KMno4, is a powerful oxiduting agent The products of a given redox reaction with the permanganato ion depend on the reaction conditions used in basic solution, tho following equation represents the reaction of this ion with a solution containing iodide

Explanation / Answer

Balancing equations

Part A)

the coefficients shown in the balnk in the given equation would be,

2,1

The final equation would be,

NO3-(aq) + Sn2+(aq) + 2H+(aq) --> NO2(aq) + Sn4+(aq) + 1H2O(l)

Part B)

The missing coefficients in the given balanced eqaution would be,

2,4

Balanced equation,

MnO4- + I- + 2H2O --> MnO2 + I2 + 4OH-

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