13 . Two freight Cars , each with a mass of 3.0x10^5 kgcollide and stick togethe

Question

13 . Two freight Cars , each with a mass of 3.0x10^5 kgcollide and stick together . One was initially moving at 2.2 m/s , and theother was at rest. what is their final speed. Im reall confused in this problem , how am i supposed to thefinal speed for both , am i even supposed to get the final speed forboth?. This problem is number 13 it came from Chapter 9 pg 238of the book Physics : Principle and Problems , the authors are zitzewitz , elliot andhaase. 13 . Two freight Cars , each with a mass of 3.0x10^5 kgcollide and stick together . One was initially moving at 2.2 m/s , and theother was at rest. what is their final speed. Im reall confused in this problem , how am i supposed to thefinal speed for both , am i even supposed to get the final speed forboth?. This problem is number 13 it came from Chapter 9 pg 238of the book Physics : Principle and Problems , the authors are zitzewitz , elliot andhaase.

Explanation / Answer

The momentum equation is m1v1 = m2v2 The momentum of the total before was (3x10^5)(2.2) +((3x10^5)(0). After: it is (3x10^5 + 3x10^5)(v) This creates the equation (3x10^5)(2.2)= (3x10^5 + 3x10^5)(v) So, v = 1.1 m/s

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