12:50 PM OO Sprint LTE 69%, livetext.com 3. A9s N force exerted at the end of a

Question

12:50 PM OO Sprint LTE 69%, livetext.com 3. A9s N force exerted at the end of a 0.50 m long torque wrench gives rise to a torque of15 Nm what is the angle (assumed to be less than 90 between the wrench handle and the direction of the applied force: a) 18%.b014 c229. d) 25° 4. Possible units for angular momentum a Kg m/s, b) Nis, ON/s. d)Js, e)Js 15. 15. State the two conditions for equilbrium. Two balls, each with mass S kg, and velocities of 4 m/s and 3m/s collide head on. Their final velocities are 3 m/s and 2 m/s, respectively. Is this collision elastic or inelastic? 2 Block A (mass 26 kg) slides into block B(mass 34 kg along a frictionless surface. The rection of three velocities before (0 and after the collision are indicated the corresponding speeds are va 5,5 m/s, and ven 49m/s. What are the al speed and direction (eft or rightl of velocity VA and b) is the collision is elastic 3 A uniform disk of mass M 1 20kg, Colling smoothly with a speed 342 mls What is the kinetis energx of each wheel. Comega) w moment of intertia of the uniform disk MR2 4. Find the young s modulus of elasticity for the material which is which is 2mhong, has cross sectional area 112s 10 m Tie material is subjected to axial force of 4200 x 102N As a result material is stretched Q.0242m. 5. Earth rotates about this axis once each day approximately 23.93 hours). Assume the Earth angularselokiruotz22x10arade Mass of the earth period of about 24 hours, it has an is 5.92x kg and radius of earth is 4x10 m. Calculate the momentofinertia and the of the earth. 6 State: alKeplers third lata. b) momentum impulse theorem

Explanation / Answer

13. Let the required angle be .

Torque T = Frsin, where is the angle between the direction of force and the position vector of the point where the force is being applied.

T = Frsin

or 15 N-m = (95N)(0.5m)sin

or = 18.40, Hnce a) 180 is the correct option.

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14. ANgular momentum is given by L = I

So units for angular momentum = kg-m2/s, as I has unit of kg-m2 and has unit of s-1

Units for energy is J = kg-m2/s2

or J.s =  kg-m2/s which is the unit we found for angular momentum.

So unit for angular momentum can be J.s. Hence e) is the correct option.

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15. The conditions for equlibrium are that sum of all external forces on a system must be zero and sum of all external torques on a system must be zero.

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This concludes the answers. Check the answer and let me know if it's correct. If you need anymore clarification or correction I will be happy to oblige....

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